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C works for 3 days finishing 1/7 of the work. Then, B works for 2 days finishing 1/7 of the work. A works for 5 days and completes the work. In how many days would A have completed the work?

C works for 3 days finishing 1/7 of the work. Then, B works for 2 days finishing 1/7 of the work. A works for 5 days and completes the work. In how many days would A have completed the work? Correct Answer 7

Given:

C works for 3 days finishing 1/7 of the work. Then, B works for 2 days finishing 1/7 of the work. A works for 5 days and completes the work.

Formula:

If a person takes x days to finish 1/y of the work, the total days taken by him to finish the entire work is x × y.

Calculation:

C and B finishes 2/7 of the work i.e. 1/7 + 1/7 = 2/7

Remaining 5/7 of work done by A in 5 days

⇒ 5/7 = 5/x

Where x is the no. of days taken by A

∴ A would have taken 7 days to complete the work.

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