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A mixture is composed of 11 parts of pure milk and 2 parts of water. If 35 litres of water were added to the mixture then the new mixture will contain twice as much pure milk as water, then how many litres of pure milk does the original mixture contain?

A mixture is composed of 11 parts of pure milk and 2 parts of water. If 35 litres of water were added to the mixture then the new mixture will contain twice as much pure milk as water, then how many litres of pure milk does the original mixture contain? Correct Answer 110

Given:

A mixture is composed of 11 parts of pure milk and 2 parts of water.

If 35 liters of water were added to the mixture then the new mixture will contain twice as much pure milk as water.

Concept :

If N is divided into two part in the ratio a : b, then

First part = N × a/(a + b)

Second part = N × b/(a + b)

Calculation:

Let the mixture is of ‘13x’ liters

Quantity of milk in the mixture = 11x liters

Quantity of water in the mixture = 2x liters

After adding 35 liters of water, new mixture has (2x + 35) part water

After adding 35 liters of water, the new mixture will contain twice as much pure milk as water.

11x/(2x + 35) = 2/1

⇒ 4x + 70 = 11x

⇒ 11x - 4x = 70

⇒ 7x = 70

⇒ x = 10 

∴ Quantity of milk in the mixture = 11x = 110 liters

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