A man divided a certain sum of money between his three sons in the ratio 4 ∶ 3 ∶ 2, such that the first son invested 1/5 of his share, the second son invested 1/4 of his share and the third son invested 1/3 of his share, and spend the remaining money. If they together invested Rs. 26600, how much total money did they spend?
A man divided a certain sum of money between his three sons in the ratio 4 ∶ 3 ∶ 2, such that the first son invested 1/5 of his share, the second son invested 1/4 of his share and the third son invested 1/3 of his share, and spend the remaining money. If they together invested Rs. 26600, how much total money did they spend? Correct Answer Rs. 81400
Let the shares of the three sons be Rs. ‘4x’, Rs. ‘3x’ and Rs. ‘2x’ respectively
⇒ Amount invested by first son = 1/5 of his share = (1/5) × 4x = (4/5)x
⇒ Amount invested by second son = 1/4 of his share = (1/4) × 3x = (3/4)x
⇒ Amount invested by third son = 1/3 of his share = (1/3) × 2x = (2/3)x
⇒ Total investment = (4/5)x + (3/4)x + (2/3)x = (48 + 45 + 40)x/60 = 133x/60
According to question,
⇒ 133x/60 = 26600
⇒ x = 26600 × (60/133) = 12000
Now,
⇒ Total money divided = 4x + 3x + 2x = 9x = 9 × 12000 = Rs. 108000
∴ Total money spent = 108000 – 26600 = Rs. 81400