Consider a combination of T and D flip-flops connected as shown below. The output of the D flip-flop is connected to the T flip-flop and the output of the T flip-flop is connected to the input of the D flip-flop. Initially, both Q0 and Q1 are set to 1 (before the 1st clock cycle). The outputs
Consider a combination of T and D flip-flops connected as shown below. The output of the D flip-flop is connected to the T flip-flop and the output of the T flip-flop is connected to the input of the D flip-flop. Initially, both Q0 and Q1 are set to 1 (before the 1st clock cycle). The outputs Correct Answer Q<sub>1 </sub>Q<sub>0</sub> after the 3<sup>rd</sup> cycle are 11 and after the 4<sup>th</sup> cycle are 01 respectively
Output of one flip- flop becomes the input of another flip- flop. Two flip flops are given T and D flip flop. We can solve it using the characteristic equation of D and T flip flop and then calculate the next states Q1N and Q0N.
Explanation:
Here, T flip flop output is denoted by Q1 and D flip flop output by Q0.
Output of D flip flop i.e. Q0 is coming at the T flip flop and Q1 is going to D flip flop as input.
So, Q1N = Q1 EXOR T = Q1 EXOR Q0
Q0N = D = Q1
Initially, Q0 = Q1 = 1
Next State Table:
|
Clock Cycle |
Q1 |
Q0 |
Q1N |
Q0N |
|
1 |
1 |
1 |
0 |
1 |
|
2 |
0 |
1 |
1 |
0 |
|
3 |
1 |
0 |
1 |
1 |
|
4 |
1 |
1 |
0 |
1 |
So, Q1Q0 after 3rd clock cycle is 11 and Q1Q0 after 4th clock cycle is 01.