In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option. Quantity A: A sum of Rs 110 is in the from of Rs. 2, Rs. 1 and 50 paise coins in the ratio of 1 : 2 : 3 respectively, how many 50 paise coins are there? Quantity B: A sum of the money was distributed among A, B, C and D in a proportion of 5 : 2 : 3 : 2 respectively. If C received Rs. 30 more than what D received, then what was B’s share?
In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option. Quantity A: A sum of Rs 110 is in the from of Rs. 2, Rs. 1 and 50 paise coins in the ratio of 1 : 2 : 3 respectively, how many 50 paise coins are there? Quantity B: A sum of the money was distributed among A, B, C and D in a proportion of 5 : 2 : 3 : 2 respectively. If C received Rs. 30 more than what D received, then what was B’s share? Correct Answer Quantity A = Quantity B or No relation
Quantity A:
Total sum = Rs. 110
Ratio of coins of Rs. 2, Rs. 1 and 50 paise = 1 : 2 : 3
Ratio of rupees of Rs. 2, Rs. 1 and 50 paise = (2 × 1) : (1 × 2) : (3/2) = 4 : 4 : 3
Let the ratio of rupees of Rs. 2, Rs. 1 and 50 paise be 4x : 4x : 3x
According to the question
(4x + 4x + 3x) = 110
x = 10
Total rupees of 50 paise = 3x = 3 × 10 = Rs. 30
Total coins of 50 paise = 30 × 2 = 60
Quantity B:
Ratio of A, B, C and D = 5x : 2x : 3x : 2x
According to the question
⇒ 3x – 2x = 30
⇒ x = 30
⇒ 2x = 30 × 2 = 60
∴ Quantity A = Quantity B or No relation