Motu and Chotu are two painters. They got a contract of painting a house. Motu does 1/4 of work what Chotu does in 1/12 of the time. If they paint together, they take 15 days to complete their task. How much time chotu take to do it alone ?
Motu and Chotu are two painters. They got a contract of painting a house. Motu does 1/4 of work what Chotu does in 1/12 of the time. If they paint together, they take 15 days to complete their task. How much time chotu take to do it alone ? Correct Answer 60 days
Given∶
Motu does 1/4 of work what Chotu does in 1/12 of the time.
They take 15 days to complete the task if they paint together.
Formula Used∶
Concept of Linear Equations and Use of Ratio in Time and Work.
Calculation∶
Let Chotu take 'a' days to complete task.
Work done by Chotu in 1 day =1/a
According to Question,
Motu does 1/4 work in a/12 days
So, Motu does the whole work in 4a/12 = a/3 days
Work done by Motu in one day = 3/a
Also, Work done by Motu and Chotu together in one day = 1/a + 3/a = 4/a
So, Time taken to complete the whole work by Motu and Chotu together = a/4 days
Again. it is given that a/4 = 15
So, a = 15 × 4 = 60 days
∴ Chotu takes 60 days to complete the task.