A and B together can complete a task in 20 days. B and C together can complete the same task in 25 days. A and C together can complete the same task in 30 days. What is the respective ratio of the number of days taken by A when completing the same task alone to the number of days taken by C when completing the same task alone?
A and B together can complete a task in 20 days. B and C together can complete the same task in 25 days. A and C together can complete the same task in 30 days. What is the respective ratio of the number of days taken by A when completing the same task alone to the number of days taken by C when completing the same task alone? Correct Answer 7 : 13
Let, Efficiency of A = x/day
Efficiency of B = y/day
Efficiency of C = z/day
∴ (A + B)’s 1 day’s work = 1/20
∴ x + y = 1/20 ----- (1)
∴ (B + C)’s 1 day’s work = 1/25
∴ y + z = 1/25 ----- (2)
∴ (C + A)’s 1 day’s work = 1/30
∴ z + x = 1/30 ----- (3)
From (1) + (2) + (3) we get,
⇒ x + y + y + z + x = 1/20 + 1/25 + 1/30
⇒ 2(x + y + z) = 37/300
⇒ x + y + z = 37/600 ----- (4)
From (4) - (1) we get,
⇒ x + y + z - (x + y) = 37/600 - 1/20
⇒ z = 7/600 ----- (5)
From (3) - (5) we get,
⇒ z + x - z = 1/30 - 7/600
⇒ x = 13/600
∴ A’s 1 day’s work = 13/600
∴ A can complete the work in = 600/13 days
∴ C’s 1 day’s work = 7/600
∴ C can complete the work in = 600/7 days
∴ required ratio,
⇒ 600/13 ∶ 600/7
⇒ 7 ∶ 13