A and B together can complete a task in 20 days. B and C together can complete the same task in 25 days. A and C together can complete the same task in 30 days. What is the respective ratio of the number of days taken by A when completing the same task alone to the number of days taken by C when completing the same task alone?

A and B together can complete a task in 20 days. B and C together can complete the same task in 25 days. A and C together can complete the same task in 30 days. What is the respective ratio of the number of days taken by A when completing the same task alone to the number of days taken by C when completing the same task alone? Correct Answer 7 : 13

Let, Efficiency of A = x/day

Efficiency of B = y/day

Efficiency of C = z/day

∴ (A + B)’s 1 day’s work = 1/20

∴ x + y = 1/20 ----- (1)

∴ (B + C)’s 1 day’s work = 1/25

∴ y + z = 1/25 ----- (2)

∴ (C + A)’s 1 day’s work = 1/30

∴ z + x = 1/30 ----- (3)

From (1) + (2) + (3) we get,

⇒ x + y + y + z + x = 1/20 + 1/25 + 1/30

⇒ 2(x + y + z) = 37/300

⇒ x + y + z = 37/600 ----- (4)

From (4) - (1) we get,

⇒ x + y + z - (x + y) = 37/600 - 1/20

⇒ z = 7/600 ----- (5)

From (3) - (5) we get,

⇒ z + x - z = 1/30 - 7/600

⇒ x = 13/600

∴ A’s 1 day’s work = 13/600

∴ A can complete the work in = 600/13 days

∴ C’s 1 day’s work = 7/600

∴ C can complete the work in = 600/7 days

∴ required ratio,

⇒ 600/13 ∶ 600/7

⇒ 7 ∶ 13

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