Abdul can complete a work in 6 days. Bhide master can complete the same work in 10 days. Champak chacha can do it in 15 days. On day 1, only Champak chacha works. On day 2, both Champak chacha and Bhide master work together. On day 3, both Champak chacha and Abdul work together. After 3 days this cycle repeats. In how many days will the work get completed? 

Abdul can complete a work in 6 days. Bhide master can complete the same work in 10 days. Champak chacha can do it in 15 days. On day 1, only Champak chacha works. On day 2, both Champak chacha and Bhide master work together. On day 3, both Champak chacha and Abdul work together. After 3 days this cycle repeats. In how many days will the work get completed?  Correct Answer 7

Given:

Time taken by Abdul = 6 days

Time taken by Bhide Master = 10 days

Time taken by Champak Chacha = 15 days

Concept:

Total Work = Efficiency × time

Calculation:

Let the total work be LCM of (6, 10, 15) i.e 30 units

Efficiency of Abdul = 30/6 = 5 unit/day

Efficiency of Bhide Master = 30/10 = 3 unit/day

Efficiency of Champak Chacha = 30/15 = 2 unit/day

Total work done on day 1 by Champak Chacha = 2 units

Total work done on day 2 by Champak Chacha and Bhide Master = (2 + 3) = 5 units

Total work done on day 3 by Champak Chacha and Abdul = (2 + 5) = 7 units

So total work done in first 3 days = 2 + 5 + 7 = 14 units

This process will repeat again for 3 days

So, total work in next 3 days = 14 units

Total work till 6 days = 14 + 14 = 28 units 

On day 7, Champak Chacha will do 2 unit work alone

So total work till 7 days = 28 + 2 = 30 units 

∴ The required time is 7 days.

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