Abdul can complete a work in 6 days. Bhide master can complete the same work in 10 days. Champak chacha can do it in 15 days. On day 1, only Champak chacha works. On day 2, both Champak chacha and Bhide master work together. On day 3, both Champak chacha and Abdul work together. After 3 days this cycle repeats. In how many days will the work get completed?
Abdul can complete a work in 6 days. Bhide master can complete the same work in 10 days. Champak chacha can do it in 15 days. On day 1, only Champak chacha works. On day 2, both Champak chacha and Bhide master work together. On day 3, both Champak chacha and Abdul work together. After 3 days this cycle repeats. In how many days will the work get completed? Correct Answer 7
Given:
Time taken by Abdul = 6 days
Time taken by Bhide Master = 10 days
Time taken by Champak Chacha = 15 days
Concept:
Total Work = Efficiency × time
Calculation:
Let the total work be LCM of (6, 10, 15) i.e 30 units
Efficiency of Abdul = 30/6 = 5 unit/day
Efficiency of Bhide Master = 30/10 = 3 unit/day
Efficiency of Champak Chacha = 30/15 = 2 unit/day
Total work done on day 1 by Champak Chacha = 2 units
Total work done on day 2 by Champak Chacha and Bhide Master = (2 + 3) = 5 units
Total work done on day 3 by Champak Chacha and Abdul = (2 + 5) = 7 units
So total work done in first 3 days = 2 + 5 + 7 = 14 units
This process will repeat again for 3 days
So, total work in next 3 days = 14 units
Total work till 6 days = 14 + 14 = 28 units
On day 7, Champak Chacha will do 2 unit work alone
So total work till 7 days = 28 + 2 = 30 units
∴ The required time is 7 days.