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Two monoshot multivibrators, are positive edge triggered (M1) and another negative edge triggered (M2), are connected as shown in figure The monoshots M1 and M2 when triggered produce pulses of width T1 and T2 respectively, where T1 > T2. The steady state output voltage v0 of the circuit is

Two monoshot multivibrators, are positive edge triggered (M1) and another negative edge triggered (M2), are connected as shown in figure The monoshots M1 and M2 when triggered produce pulses of width T1 and T2 respectively, where T1 > T2. The steady state output voltage v0 of the circuit is Correct Answer <img alt="F1 Uday Madhu 03.07.20 D 18" src="//storage.googleapis.com/tb-img/production/20/07/F1_Uday_Madhu_03.07.20_D%2018.png">

  • Mono shot multivibrators are used to generate a single output pulse of a specified width, either ‘HIGH’ or ‘LOW’, when a suitable external trigger signal or pulse T is applied.
  • Trigger signal initiates a timing cycle which causes the output of the monostable to change its state at the start of the timing cycle and will remain in this second state.

 

When monoshot multivibrator M1 is triggered, it produces a pulse of T1 duration.

Let, the output Q2 is initially high, so the output v0 will be high for a time period T2

 

Now for this period, Q̅2 = 0, so the output of AND gate is low.

For M1 is positive triggered, M1 will be OFF for duration T2.

After T2 time, Q2 = 0 and Q̅2 = 1

Hence the output of AND gate is 1 i.e. M1 is triggered and the output Q1 is high for duration T1.

For M2 is negative edge triggered, M2 will be off for the duration T1 and hence, output v0 will be as

After T1 time the output Q1 becomes low, and M2 gets ON due to negative edge triggering. Hence the cycle continues as given below.

[ alt="F1 Uday Madhu 03.07.20 D 18" src="//storage.googleapis.com/tb-img/production/20/07/F1_Uday_Madhu_03.07.20_D%2018.png" style="width: 320px; height: 91px;">

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