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In a school function sweets are distributed among students. Initially the number of male and female students is 3 ∶ 2 when 50 female students are added the ratio becomes 4 ∶ 3. Now the sweets received by male and female students are equal. Calculate the sweets distributed among students earlier, if female students get 1 sweet more than male students.

In a school function sweets are distributed among students. Initially the number of male and female students is 3 ∶ 2 when 50 female students are added the ratio becomes 4 ∶ 3. Now the sweets received by male and female students are equal. Calculate the sweets distributed among students earlier, if female students get 1 sweet more than male students. Correct Answer 3400

Given:

Ratio of male and female students = 3 ∶ 2

Calculation:

Ratio of male and female students = 3 ∶ 2

Let male students be 3x and female students be 2x

When 50 students is female students are added the ratio becomes 4 ∶ 3

⇒ [3x/(2x + 50)} = 4/3

⇒ 9x = 8x + 200

⇒ x = 200

Number of male students = 3 × 200 = 600

Number of female students = 2 × 200 = 400

50 female students are added

Number of female students = 400 + 50 = 450

Sweets received by male and female students are equal

Let y be the number of sweets received by each male student and (y + 1) be the number of sweets received by each female students

⇒ 450(y + 1) = 600y

⇒ 450y + 450 = 600y

⇒ 150y = 450

⇒ y = 3

Number of sweets received by each male student = 3

Number of sweets received by each female students = 4

⇒ Number of female students earlier = 400

The sweets distributed among students

⇒ (400 × 4) + (600 × 3)

⇒ 1600 + 1800 = 3400

∴ The sweets distributed among students is 3400.

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