In a JFET, the drain current is maximum when VGS is

In a JFET, the drain current is maximum when VGS is Correct Answer Zero

Explanation:

The cross-sectional view of the n – channel JFET is shown below.

1) As VGS is negative, both P+n regions are reverse biased, and hence the depletion region increases, and as a result channel width decreases.

2) As VGS becomes more negative, more depletion region is formed and channel thickness (tch) decreases. Thus the area of channel increases. Hence JFET can be used as a “Voltage Variable resistor”.

The drain characteristics of the n – channel JFET is shown below:

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When VGS = 0, then JFET works in the saturation region. So, the drain current will be more and saturated.

Related Questions

When VDS is the drain voltage and VDS(max) is the maximum drain voltage, the JFET will breakdown if: