A manufacturer sold an item to A at 10% profit who sold it to B at 20% profit and finally B sold it to C for Rs ‘P’ at a 15% loss. If the manufacture had directly sold the item to C at Rs ‘P’, he would have gained Rs. 427 profit, then what is the cost of the item for the manufacturer?

A manufacturer sold an item to A at 10% profit who sold it to B at 20% profit and finally B sold it to C for Rs ‘P’ at a 15% loss. If the manufacture had directly sold the item to C at Rs ‘P’, he would have gained Rs. 427 profit, then what is the cost of the item for the manufacturer? Correct Answer Rs. 3500

Let cost of item for manufacturer be 100x

CP for A = 110% of 100x = 110x

CP for B = 120% of 110x = 132x

CP for C = 85% of 132x = 112.2x = P

According to the question,

(100x + 427) = P

⇒ 112.2x = 100x + 427

⇒ 12.2x = 427

⇒ x = 35

∴ Cost of item for manufacturer = 100x = Rs. 3500

Related Questions

Each question below is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer. The combined cost of three articles in a shop is Rs.4200. Two article sold at profit of 25% and 12.5% and third article is sold such that there is a loss of Rs.630. What is the loss percentage incurred on third article. I. The difference between cost price of highest article and lowest article is Rs.600. The costliest article is sold at a loss.  II, The cheapest item is sold at 25% profit. The the price of one of that article is the average price of the cheapest and costliest item.