Three vessels, whose capacities are 3, 4, and 5 liters, contain solutions of acid and water, in which the ratio of acid and water is 2 : 3, 3 : 7, and 4 : 11 respectively. The ratio of acid and water in the final solution thus obtained is:
Three vessels, whose capacities are 3, 4, and 5 liters, contain solutions of acid and water, in which the ratio of acid and water is 2 : 3, 3 : 7, and 4 : 11 respectively. The ratio of acid and water in the final solution thus obtained is: Correct Answer 14 : 31
Given:
Three vessels, whose capacities are 3, 4, and 5 liters, contain solutions of acid and water, in which the ratio of acid and water is 2 : 3, 3 : 7, and 4 : 11 respectively.
Calculation:
According to the question,
In vessels A,
Acid = 3 × 2/5 = 6/5
Water = 3 × 3/5 = 9/5
In vessels B,
Acid = 4 × 3/10 = 6/5
Water = 4 × 7/10 = 14/5
In vessels C,
Acid = 5 × 4/15 = 4/3
Water = 5 × 11/15 = 11/3
Total Acid = 6/5 + 6/5 + 11/3 = 56/15
Total water = 9/5 + 14/5 + 11/3 = 124/15
Ratio (in final solution) = A : W= 56/15 : 124/15 = 56 : 124 = 14 : 31
∴ The ratio of acid and water in the final solution thus obtained is 14 : 31.