With usual notations the depth of the neutral axis of a balanced section, is given by

A $$\frac{{{\text{mc}}}}{{\text{t}}} = \frac{{{\text{d}} - {\text{n}}}}{{\text{n}}}$$
B $$\frac{{\text{t}}}{{{\text{mc}}}} = \frac{{\text{n}}}{{{\text{d}} - {\text{n}}}}$$
C $$\frac{{\text{t}}}{{{\text{mc}}}} = \frac{{{\text{d}} + {\text{n}}}}{{\text{n}}}$$
D $$\frac{{{\text{mc}}}}{{\text{t}}} = \frac{{\text{n}}}{{{\text{d}} - {\text{n}}}}$$

Correct Answer: $$\frac{{{\text{mc}}}}{{\text{t}}} = \frac{{\text{n}}}{{{\text{d}} - {\text{n}}}}$$

Bissoy MCQ
#Civil Engineering #RCC Structures Design

Related Questions

If the depth of actual neutral axis in a beam is more than the depth of critical neutral axis, then the beam is called
A Balanced beam
B Under reinforced beam
C Over reinforced beam
D None of the above
In case of an under-reinforced beam, the depth of actual neutral axis is __________ that of the critical neutral axis.
A Same as
B Less than
C Greater than
D None of these
If the depth of neutral axis for a singly reinforced rectangular section is represented by kd in working stress design, then the value of k for balanced section
A depends on as, only
B depends on aCbC only
C depends on both crst and acbc
D is independant of both ast and acbc where d is the effective depth, ast is per-missible stress in steel in tension and ocbc is permissible stress in concrete in bending compression.
In a D.C. generator the magnetic neutral axis coincides with the geometrical neutral axis, when
A There is no load on the generator
B The generator runs on full load
C The generator runs on overload
D The generator runs on designed speed
By walking at 3/4 of his usual speed, a man reaches his office 20 minutes later than usual. His usual time is :
A 30 minutes
B 75 minutes
C 45 minutes
D 60 minutes
With usual notations for different parameters involved, the maximum fluctuations of energy for a flywheel is given by
A $$2{\text{E}}{{\text{C}}_{\text{S}}}$$
B $$\frac{{{\text{E}}{{\text{C}}_{\text{S}}}}}{2}$$
C $$2{\text{EC}}_{\text{S}}^2$$
D $$2{{\text{E}}^2}{{\text{C}}_{\text{S}}}$$
If the modular ratio is ‘m’, steel ratio is ‘r’ and overall depth of a beam is ‘d’, the depth of the critical neutral axis of the beam, is
A $$\frac{{\text{m}}}{{{\text{m}} - {\text{r}}}} \times {\text{d}}$$
B $$\frac{{\text{m}}}{{{\text{m}} + {\text{r}}}} \times {\text{d}}$$
C $$\frac{{{\text{m}} + {\text{r}}}}{{\text{m}}} \times {\text{d}}$$
D $$\frac{{{\text{r}} - {\text{m}}}}{{\text{m}}} \times {\text{d}}$$
If d and n are the effective depth and depth of the neutral axis respectively of a singly reinforced beam, the lever arm of the beam, is
A d
B n
C $${\text{d}} + \frac{{\text{n}}}{3}$$
D $${\text{d}} - \frac{{\text{n}}}{3}$$
In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good
A $$\frac{{{\text{mc}}}}{{\text{t}}} = \frac{{\text{n}}}{{{\text{d}} - {\text{n}}}}$$
B $$\frac{{{\text{m}} + {\text{c}}}}{{\text{t}}} = \frac{{\text{n}}}{{{\text{d}} + {\text{n}}}}$$
C $$\frac{{{\text{t}} + {\text{c}}}}{{\text{m}}} = \frac{{{\text{d}} + {\text{n}}}}{{\text{n}}}$$
D $$\frac{{\text{m}}}{{{\text{t}} + {\text{c}}}} = \frac{{\text{n}}}{{{\text{d}} - {\text{n}}}}$$
According to ISI recommendations, the maximum depth of stress block for balanced section of a beam of effective depth d is
A 0.43 d
B 0.55 d
C 0.68 d
D 0.85 d

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