Related Questions

Draught produced by a tall chimney due to density difference between hot flue gas inside the Chimney and atmospheric air outside the chimney is more appropriately known as the __________ draught.
A Natural
B Induced
C Forced
D Chimney
For maximum discharge through a chimney, its height should be
A 200 meters
B Infinitely long
C More than 105.7 metres
D Equal to the height of the hot gas column producing draught
For maximum discharge through a chimney, the condition is that height of hot gas column producing the draught should be
A One-half the height of chimney
B Equal to the height of chimney
C Two times the height of chimney
D Four times the height of chimney
The draught produced by steel chimney as compared to that produced by brick chimney for the same height is
A Less
B More
C Same
D May be more or less
The draught produced, for a given height of the chimney and given mean temperature of chimney gases
A decreases with increase in outside air temperature
B increases with increase in outside air temperature
C remains the same irrespective of outside air temperature
D may increase or decrease with increase in outside air temperature
Flue gas discharge velocity through chimney of a big thermal power plant may be around __________ m/sec.
A 0.5
B 500
C 10
D 50
The discharge over the trapezoidal notch is equal to the discharge over the rectangular notch __________ the discharge over the triangular notch.
A Plus
B Minus
C Divide
D None of these
The discharge through a convergent mouthpiece is __________ the discharge through an internal mouthpiece of the same diameter and head of water.
A Equal to
B One-half
C Three fourth
D Double
The critical depth for a channel is given by (where q = Unit discharge (discharge per unit width) through the channel)
A $${\left( {\frac{{\text{q}}}{{\text{g}}}} \right)^{\frac{1}{2}}}$$
B $${\left( {\frac{{{{\text{q}}^2}}}{{\text{g}}}} \right)^{\frac{1}{3}}}$$
C $${\left( {\frac{{{{\text{q}}^3}}}{{\text{g}}}} \right)^{\frac{1}{4}}}$$
D $${\left( {\frac{{{{\text{q}}^4}}}{{\text{g}}}} \right)^{\frac{1}{5}}}$$
The ratio of actual discharge to theoretical discharge through an orifice is equal to
A Cc.Cv
B Cc.Cd
C Cv.Cd
D $$\frac{{{{\text{C}}_{\text{d}}}}}{{{{\text{C}}_{\text{v}}}}}$$

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