The critical depth for a channel is given by (where q = Unit discharge (discharge per unit width) through the channel)

A $${\left( {\frac{{\text{q}}}{{\text{g}}}} \right)^{\frac{1}{2}}}$$
B $${\left( {\frac{{{{\text{q}}^2}}}{{\text{g}}}} \right)^{\frac{1}{3}}}$$
C $${\left( {\frac{{{{\text{q}}^3}}}{{\text{g}}}} \right)^{\frac{1}{4}}}$$
D $${\left( {\frac{{{{\text{q}}^4}}}{{\text{g}}}} \right)^{\frac{1}{5}}}$$

Correct Answer: $${\left( {\frac{{{{\text{q}}^2}}}{{\text{g}}}} \right)^{\frac{1}{3}}}$$

Related Questions

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