If B and d are the bed width and depth of a channel in meters, the combined losses due to evaporation and seepage in cumecs per kilometer length of the channel, is
A
$$\frac{1}{{50}} \times {\left( {{\text{B}} + {\text{d}}} \right)^{\frac{2}{3}}}$$
B
$$\frac{1}{{100}} \times {\left( {{\text{B}} + {\text{d}}} \right)^{\frac{2}{3}}}$$
C
$$\frac{1}{{150}} \times {\left( {{\text{B}} + {\text{d}}} \right)^{\frac{2}{3}}}$$
D
$$\frac{1}{{200}} \times {\left( {{\text{B}} + {\text{d}}} \right)^{\frac{2}{3}}}$$
Correct Answer: $$\frac{1}{{200}} \times {\left( {{\text{B}} + {\text{d}}} \right)^{\frac{2}{3}}}$$
