Related Questions

If the velocity of flow through a wide rectangular channel is 2m⁄s and the rate of change of depth is 3×10-5m, calculate the manning’s constant of the channel if the uniform flow depth is 1m and yn=0.6m. Given: Critical depth = 0.5m.
If the depth of water in an open channel is greater than the critical depth, the flow is called
In open channel flow in a rectangular channel, the ratio between the critical depth and the initial depth, when a hydraulic jump occurs is
According to Kennedy, the critical velocity (V0) in meters in a channel is the mean velocity which keeps the channel free from silting or scouring. Its value is given by (where m is critical velocity ratio and D is the depth of the channel).
The ratio of the depth of flow to the diameter of the channel for maximum discharge in a circular channel in open channel flow is
Normal depth in open channel flow is the depth of flow in the channel
Calculate the corresponding hydraulic mean depth that would exist in the channel if the bed was unrippled. The rugosity coefficient in an unrippled channel is 0.015 and the rugosity coefficient actually observed by experiments on the rippled bed of channel is 0.020. Consider the value of hydraulic mean depth of the channel as 1.5 m.
From the given below statements, find the incorrect statement. i. A critical path has zero float. ii. A critical path has both critical and non-critical activities. iii. A critical path is the longest path and consumes maximum time and resources.
If the ratio of GVF depth to normal depth and the ratio of critical depth to normal are equal to 0.5, calculate the rate of change of depth if the bed slope of the channel is 1 in 1300.
The ratio of the hydraulic radius to the diameter of the channel, for maximum mean velocity of flow in a circular channel, in open channel flow is