If the optimistic time, most likely time and pessimistic time for activity A are 4, 6 and 8 respectively and for activity B are 5, 5.5 and 9 respectively, then

If to, tp and tm are the optimistic, pessimistic and most likely time estimates of an activity respectively, the expected time t of the activity will be

A

to + 3tm+ tp/3

B

to + 4tm+ tp/4

C

to + 4tm+ tp/5

D

to + 4tm+ tp/6

If t_o, t_p and t_m are the optimistic, pessimistic and most likely time estimates of an activity respectively, the expected time t of the activity will be

A

$$\frac{{{{\text{t}}_{\text{o}}} + 3{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{2}$$

B

$$\frac{{{{\text{t}}_{\text{o}}} + 3{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{3}$$

C

$$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{4}$$

D

$$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{5}$$

E

$$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{m}}} + {{\text{t}}_{\text{p}}}}}{6}$$

If a is the optimistic time, b is the pessimistic time and m is most likely time of an activity, the expected time of the activity, is

A

$$\frac{{{\text{a}} + {\text{m}} + {\text{b}}}}{6}$$

B

$$\frac{{{\text{a}} + 2{\text{m}} + {\text{b}}}}{6}$$

C

$$\frac{{{\text{a}} + 4{\text{m}} + {\text{b}}}}{6}$$

D

$$\frac{{{\text{a}} + 5{\text{m}} + {\text{b}}}}{6}$$

If an activity has its optimistic, most likely and pessimistic times as 2, 3 and 7 respectively, then its expected time and variance are respectively

A

3.5 and $$\frac{5}{6}$$

B

5 and $$\frac{{25}}{{36}}$$

C

3.5 and $$\frac{{25}}{{36}}$$

D

4 and $$\frac{5}{6}$$

In PERT analysis, the expected time to complete an activity is computed from the three time estimates : a most likely time (m), an optimistic time (a), and pessimistic time (b) using the expression

A

$$\frac{{\left( {a + 4m + b} \right)}}{6}$$

B

$$\frac{{\left( {4a + m + b} \right)}}{6}$$

C

$$\frac{{\left( {a + m + 4b} \right)}}{6}$$

D

$$\frac{{\left( {a + m + b} \right)}}{3}$$

Consider the following statements.
1. In PERT, it is assumed that the activity times follow the beta distribution.
2. In CPM, two time and cost estimates are made for each activity, which are called the optimistic and pessimistic estimates.
3. Time is the only variable used in PERT.
4. While in PERT the emphasise is on event, in CPM the emphasise is on activity.

A

While 1 and 2 are false, 3 and 4 are true

B

1, 3 and 4 are true

C

All of the aboveare false

D

All of the above are true

For a given activity, the optimistic time, pessimistic time and the most probable estimates are 5, 17 and 8 days respectively, The expected time is

A

8 days

B

9 days

C

10 days

D

15 days

Optimistic time, most likely time and pessimistic times for the activities of a network in the given figure are written above their arrows. If the contractual obligation time for the project is 75, the latest occurrence time for the event 2, is
Construction Planning and Management mcq question image

Construction Planning and Management mcq question image

A

20

B

25

C

35

D

15

The probabilistic time is given by (where to = Optimistic time, tp = Pessimistic time, and tn = Most likely time)

A

(to + tp + tn)/3

B

(to + 2tp + tn)/4

C

(to + 4tp + tn)/5

D

(to + tp + 4tn)/6

The probabilistic time is given by (where t_o = Optimistic time, t_p = Pessimistic time and t_n = Most likely time)

A

$$\frac{{{{\text{t}}_{\text{o}}} + {{\text{t}}_{\text{p}}} + {{\text{t}}_{\text{n}}}}}{3}$$

B

$$\frac{{{{\text{t}}_{\text{o}}} + 2{{\text{t}}_{\text{p}}} + {{\text{t}}_{\text{n}}}}}{4}$$

C

$$\frac{{{{\text{t}}_{\text{o}}} + 4{{\text{t}}_{\text{p}}} + {{\text{t}}_{\text{n}}}}}{5}$$

D

$$\frac{{{{\text{t}}_{\text{o}}} + {{\text{t}}_{\text{p}}} + 4{{\text{t}}_{\text{n}}}}}{6}$$

If the optimistic time, most likely time and pessimistic time for activity A are 4, 6 and 8 respectively and for activity B are 5, 5.5 and 9 respectively, then

Related Questions