If a is the optimistic time, b is the pessimistic time and m is most likely time of an activity, the expected time of the activity, is
A
$$\frac{{{\text{a}} + {\text{m}} + {\text{b}}}}{6}$$
B
$$\frac{{{\text{a}} + 2{\text{m}} + {\text{b}}}}{6}$$
C
$$\frac{{{\text{a}} + 4{\text{m}} + {\text{b}}}}{6}$$
D
$$\frac{{{\text{a}} + 5{\text{m}} + {\text{b}}}}{6}$$
Correct Answer: $$\frac{{{\text{a}} + 4{\text{m}} + {\text{b}}}}{6}$$
