Related Questions

The bending moment at a section tends to bend or deflect the beam and the internal stresses resist its bending. The resistance offered by the internal stresses, to the bending, is called
A Compressive stress
B Shear stress
C Bending stress
D Elastic modulus
If W is total load per unit area on a panel, D is the diameter of the column head, L is the span in two directions, then the sum of the maximum positive bending moment and average of the negative bending moment for the design of the span of a square flat slab, should not be less than
A $$\frac{{{\text{WL}}}}{{12}}{\left( {{\text{L}} - \frac{{2{\text{D}}}}{3}} \right)^2}$$
B $$\frac{{{\text{WL}}}}{{10}}{\left( {{\text{L}} + \frac{{2{\text{D}}}}{3}} \right)^2}$$
C $$\frac{{{\text{WL}}}}{{10}}{\left( {{\text{L}} - \frac{{2{\text{D}}}}{3}} \right)^2}$$
D $$\frac{{{\text{WL}}}}{{12}}{\left( {{\text{L}} - \frac{{\text{D}}}{3}} \right)^2}$$
A shaft of diameter D is subjected to a twisting moment (T) and a bending moment (M). If the maximum bending stress is equal to maximum shear stress developed, then M is equal to
A $$\frac{{\text{T}}}{2}$$
B T
C 2T
D 4T
When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to
A $$\frac{1}{2}\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
B $$\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
C $$\frac{1}{2}\left( {{\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} } \right)$$
D $${\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
‘P’ is the pre-stressed force applied to tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The minimum stress ‘f’ on the beam subjected to a maximum bending moment ‘M’ is
A $${\text{f}} = \frac{{\text{P}}}{{\text{A}}} - \frac{{\text{Z}}}{{\text{M}}}$$
B $${\text{f}} = \frac{{\text{A}}}{{\text{P}}} - \frac{{\text{M}}}{{\text{Z}}}$$
C $${\text{f}} = \frac{{\text{P}}}{{\text{A}}} - \frac{{\text{M}}}{{\text{Z}}}$$
D $${\text{f}} = \frac{{\text{P}}}{{\text{A}}} - \frac{{\text{M}}}{{6{\text{Z}}}}$$
‘P’ is the pre-stressed force applied to the tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The maximum stress ‘f’ in the beam, subjected to a maximum bending moment ‘M’, is
A $${\text{f}} = \frac{{\text{P}}}{{\text{A}}} - \frac{{\text{Z}}}{{\text{M}}}$$
B $${\text{f}} = \frac{{\text{A}}}{{\text{P}}} - \frac{{\text{M}}}{{\text{Z}}}$$
C $${\text{f}} = \frac{{\text{P}}}{{\text{A}}} - \frac{{\text{M}}}{{\text{Z}}}$$
D $${\text{f}} = \frac{{\text{P}}}{{\text{A}}} - \frac{{\text{M}}}{{6{\text{Z}}}}$$
In a simple bending theory, one of the assumptions is that the plane sections before bending remain plane after bending. This assumption means that
A Stress is uniform throughout the beam
B Strain is uniform throughout the beam
C Stress is proportional to the distance from the neutral axis
D Strain is proportional to the distance from the neutral axis
A beam supporting a uniformly distributed load over its entire length L is pinned at one end and passes over a roller support at a distance x from the other end . The value of x such that the greatest bending moment in the beam is as small as possible, will be
A 0.293L
B 0.330L
C 0.111L
D 0.125L
A simply supported beam carries varying load from zero at one end and w at the other end. If the length of the beam is a, the maximum bending moment will be
A $$\frac{{{\text{wa}}}}{{27}}$$
B $$\frac{{{\text{w}}{{\text{a}}^2}}}{{27}}$$
C $$\frac{{{{\text{w}}^2}{\text{a}}}}{{\sqrt {27} }}$$
D $$\frac{{{\text{w}}{{\text{a}}^2}}}{{9\sqrt 3 }}$$
The maximum bending moment of a simply supported beam of span $$l$$ and carrying a point load W at the center of beam, is
A $$\frac{{{\text{W}}l}}{4}$$
B $$\frac{{{\text{W}}l}}{2}$$
C $${\text{W}}l$$
D $$\frac{{{\text{W}}{l^2}}}{4}$$

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