A beam supporting a uniformly distributed load over its entire length L is pinned at one end and passes over a roller support at a distance x from the other end . The value of x such that the greatest bending moment in the beam is as small as possible, will be

A 0.293L
B 0.330L
C 0.111L
D 0.125L

Correct Answer: 0.293L

David Cohen Award is the biggest literary award of Britain. The David Cohen Prize has established itself as the greatest honour a British or Irish writer can receive within these islands.
Bissoy MCQ
#সাধারণ বিজ্ঞান #Bangladesh Bank #রোধ #Assistant Director (Engineering -Mechanical) | 11.01.2019

Related Questions

When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies
A Less than the left half span
B Whole of left half span
C More than the left half span
D Whole span
The simply supported beam 'A' of length '$$l$$' carries a central point load 'W'. Another beam 'B' is loaded with a uniformly distributed load such that the total load on the beam is 'W'. The ratio of maximum deflections between beams 'A' and 'B' is
A $$\frac{5}{8}$$
B $$\frac{8}{5}$$
C $$\frac{5}{4}$$
D $$\frac{4}{5}$$
The bending moment of a cantilever beam of length '$$l$$' and carrying a uniformly distributed load of 'w' per unit length is __________ at the fixed end.
A $$\frac{{{\text{w}}l}}{4}$$
B $$\frac{{{\text{w}}l}}{2}$$
C $${\text{w}}l$$
D $$\frac{{{\text{w}}{l^2}}}{2}$$
A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be
A $$\frac{2}{3}$$
B $$\frac{3}{2}$$
C $$\frac{5}{8}$$
D $$\frac{8}{5}$$
A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is
A 0.207
B 0.307
C 0.407
D 0.508
The natural frequency of free transverse vibrations due to uniformly distributed load acting over a simply supported shaft is (where $$\delta {\text{S}}$$ = Static deflection of simply supported shaft due to uniformly distributed load)
A $$\frac{{0.4985}}{{\sqrt {\delta {\text{S}}} }}$$
B $$\frac{{0.5615}}{{\sqrt {\delta {\text{S}}} }}$$
C $$\frac{{0.571}}{{\sqrt {\delta {\text{S}}} }}$$
D $$\frac{{0.6253}}{{\sqrt {\delta {\text{S}}} }}$$
A load which is spread over a beam in such a manner that it varies uniformly over the whole length of abeam is called uniformly ________ load.
A Distributed
B Varying
C Both A and B
D None of these
The bending moment in the center of a simply supported beam carrying a uniformly distributed load of w per unit length is
A Zero
B $$\frac{{{\text{w}}{l^2}}}{2}$$
C $$\frac{{{\text{w}}{l^2}}}{4}$$
D $$\frac{{{\text{w}}{l^2}}}{8}$$
The bending moment diagram for a simply supported beam carrying a uniformly distributed load of ‘w’ per unit length, will be
A A horizontal line
B A vertical line
C An inclined line
D A parabolic curve
A simply supported beam carries varying load from zero at one end and w at the other end. If the length of the beam is a, the maximum bending moment will be
A $$\frac{{{\text{wa}}}}{{27}}$$
B $$\frac{{{\text{w}}{{\text{a}}^2}}}{{27}}$$
C $$\frac{{{{\text{w}}^2}{\text{a}}}}{{\sqrt {27} }}$$
D $$\frac{{{\text{w}}{{\text{a}}^2}}}{{9\sqrt 3 }}$$

Next steps