The maximum height of a projectile on a horizontal plane, is
A
$$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{2{\text{g}}}}$$
B
$$\frac{{{{\text{u}}^2}{{\cos }^2}\alpha }}{{2{\text{g}}}}$$
C
$$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{\text{g}}}$$
D
$$\frac{{{{\text{u}}^2}{{\cos }^2}\alpha }}{{\text{g}}}$$
Correct Answer: $$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{2{\text{g}}}}$$