The maximum height of a projectile on a horizontal plane, is

$$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{2{\text{g}}}}$$

$$\frac{{{{\text{u}}^2}{{\cos }^2}\alpha }}{{2{\text{g}}}}$$

$$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{\text{g}}}$$

$$\frac{{{{\text{u}}^2}{{\cos }^2}\alpha }}{{\text{g}}}$$

The maximum height of a projectile on a horizontal plane, is Correct Answer $$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{2{\text{g}}}}$$

Bissoy MCQ Team

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