For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is
A
$$\alpha = \frac{\pi }{4} - \frac{\beta }{2}$$
B
$$\alpha = \frac{\pi }{2} + \frac{\beta }{2}$$
C
$$\alpha = \frac{\beta }{2} - \frac{\pi }{2}$$
D
$$\alpha = \frac{\pi }{4} - \frac{\beta }{4}$$
E
$$\alpha = \frac{\pi }{2} - \frac{\beta }{2}$$
Correct Answer: $$\alpha = \frac{\pi }{2} + \frac{\beta }{2}$$
