Related Questions

The range of projectile on a downward inclined plane is ________ the range on upward inclined plane for the same velocity of projection and angle of projection.
A Less than
B More than
C Equal to
D None of these
If the direction of projection bisects the angle between the vertical and the inclined plane, then the range of projectile on the inclined plane is
A Zero
B Maximum
C Minimum
D None of these
For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is
A $$\alpha = \frac{\pi }{4} - \frac{\beta }{2}$$
B $$\alpha = \frac{\pi }{2} + \frac{\beta }{2}$$
C $$\alpha = \frac{\beta }{2} - \frac{\pi }{2}$$
D $$\alpha = \frac{\pi }{4} - \frac{\beta }{4}$$
E $$\alpha = \frac{\pi }{2} - \frac{\beta }{2}$$
The range of projectile will be maximum for a given velocity of projectile, when the angle of projection ($$\alpha $$) is
A $$\frac{\beta }{2}$$
B 30° + $$\frac{\beta }{2}$$
C 45° + $$\frac{\beta }{2}$$
D 60° + $$\frac{\beta }{2}$$
The velocity ratio in case of an inclined plane inclined at angle 'θ' to the horizontal and weight being pulled up the inclined plane by vertical effort is
A sinθ
B cosθ
C tanθ
D cosecθ
For maximum range of a projectile, the angle of projection should be
A 30°
B 45°
C 60°
D None of these
The angle of projection at which the horizontal range and maximum height of a projectile are equal to
A 36°
B 45°
C 56°
D 76°
For a given velocity of a projectile, the range is maximum when the angle of projection is
A 30°
B 45°
C 90°
D 0°
The range of a projectile is maximum, when the angle of projection is
A 30°
B 45°
C 60°
D 90°
The range of projectile (R) on an upward inclined plane is
A $$\frac{{{\text{g}}{{\cos }^2}\beta }}{{2{{\text{u}}^2}\sin \left( {\alpha + \beta } \right)\cos \alpha }}$$
B $$\frac{{2{{\text{u}}^2}\sin \left( {\alpha + \beta } \right)\cos \alpha }}{{{\text{g}}{{\cos }^2}\beta }}$$
C $$\frac{{{\text{g}}{{\cos }^2}\beta }}{{2{{\text{u}}^2}\sin \left( {\alpha - \beta } \right)\cos \alpha }}$$
D $$\frac{{2{{\text{u}}^2}\sin \left( {\alpha - \beta } \right)\cos \alpha }}{{{\text{g}}{{\cos }^2}\beta }}$$

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