The range of projectile will be maximum for a given velocity of projectile, when the angle of projection ($$\alpha $$) is
A
$$\frac{\beta }{2}$$
B
30° + $$\frac{\beta }{2}$$
C
45° + $$\frac{\beta }{2}$$
D
60° + $$\frac{\beta }{2}$$
Correct Answer: 45° + $$\frac{\beta }{2}$$