The time of flight (t) of a projectile on a horizontal plane is given by
A
$${\text{t}} = \frac{{2{\text{u}}\sin \alpha }}{{\text{g}}}$$
B
$${\text{t}} = \frac{{2{\text{u}}\cos \alpha }}{{\text{g}}}$$
C
$${\text{t}} = \frac{{2{\text{u}}\tan \alpha }}{{\text{g}}}$$
D
$${\text{t}} = \frac{{2{\text{u}}}}{{{\text{g}}\sin \alpha }}$$
Correct Answer: $${\text{t}} = \frac{{2{\text{u}}\sin \alpha }}{{\text{g}}}$$