A vessel contains milk and water in the ratio 3 : 2. The volume of the contents is increased by 50% by adding water to it. From this resultant solution 30 L is withdrawn and then replaced with water. The resultant ratio of milk water in the final solution is 3 : 7. Find the original volume of the solution.

A vessel contains milk and water in the ratio 3 : 2. The volume of the contents is increased by 50% by adding water to it. From this resultant solution 30 L is withdrawn and then replaced with water. The resultant ratio of milk water in the final solution is 3 : 7. Find the original volume of the solution. Correct Answer 80 L

Let the original volume be x. then, quantity of milk and water, = $$\frac{{3x}}{5}$$ and $$\frac{{2x}}{5}$$ respectively. After adding water to it, the volume becomes 150%, the quantity of milk and water, = $$\frac{{3x}}{5}$$ and $$\frac{{9x}}{10}$$$$\frac{{\frac{{3x}}{5} - 12}}{{\frac{{9x}}{{10}} + 12}} = \frac{3}{7}$$14(3x - 60) = 3(9x + 120)Or, x = 80 L

Related Questions

Each question below is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer. What is the ratio of coconut oil and milk in the final beaker? If contents from four vessels poured in it. I. Vessel B has 10 ml more capacity than vessel A and the ratio of coconut oil and milk in vessel B is 2 ∶ 7. Vessel C has coconut oil and milk in the ratio 2 ∶ 3 and contains 38 ml more capacity than Vessel D II. Vessel A has milk and coconut oil in the ratio 3 ∶ 5. Vessel C has 12 ml more coconut oil than vessel D.