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A vessel has 30 litres of mixture water and milk. The second vessel has 20 litres of mixed milk and water are in ratio 3 : 2 respectively. How much milk present in the first vessel if the water present in the first vessel is 50% more than the milk present in the second vessel?

A vessel has 30 litres of mixture water and milk. The second vessel has 20 litres of mixed milk and water are in ratio 3 : 2 respectively. How much milk present in the first vessel if the water present in the first vessel is 50% more than the milk present in the second vessel? Correct Answer 12 

Given:

The first vessel has 30 litres of mixture

The second vessel has 20 litres of mixture

Concept:

Mixtures and alligations

Calculation:

⇒ Second vessel have milk = (3/5) × 20 = 12 liters

⇒ Water present in first vessel = (3/2) × 12 = 18 liters

⇒ Milk present in first vessel = 30 - 18 = 12 liters

∴ The required result will be 12 litres.

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