A train left from station A for station B at 4pm at an average speed of 80 kmph. At 8 pm,another train also had left from station A forstation B on a parallel track at an averagespeed of 120 kmph. How far from A is anothertrain expected to overtake the first train?

A train left from station A for station B at 4pm at an average speed of 80 kmph. At 8 pm,another train also had left from station A forstation B on a parallel track at an averagespeed of 120 kmph. How far from A is anothertrain expected to overtake the first train? Correct Answer 960km

Ans. Distance covered by 1st train in 4 hours = 80*4 = 320 kmRelative speed of 2nd train = 120-80 = 40 kmIt will overtake another train in 320/40 = 8 hoursDistance between overtake point and station A = 8*120 = 960 km

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