In the face-centered cubic structure, the (111) octahedral planes and the (110) directions are the close-packed systems. What is the total number of possible slip system in FCC?

In the face-centered cubic structure, the (111) octahedral planes and the (110) directions are the close-packed systems. What is the total number of possible slip system in FCC? Correct Answer 12

There are eight (111) planes in the fcc unit cell. However, the planes at opposite faces of the octahedron are parallel to each other, so that there are only four sets of octahedral planes. Each (111) plane contains three (110) directions (the reverse directions being neglected). Therefore, the fcc lattice has 12 possible slip systems.

Related Questions

111, 111, 111, 111 is divisible by :
In a cubic crystal, atoms of mass M1 lie on one set of planes and atoms of mass M2 lie on planes interleaved between those of the first set. If C is the forte constant between nearest neighbour planes, the frequency of lattice vibrations for the optical phonon branch with wave vector k = 0 is