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Numbers 29, 30, 31, ....., 88, 89 and 90 are written on slips (one number on one slip) and these slips are kept in a box. Then, a slip is drawn from the box at random. What is the probability that number in the drawn slip is not a prime number?

Numbers 29, 30, 31, ....., 88, 89 and 90 are written on slips (one number on one slip) and these slips are kept in a box. Then, a slip is drawn from the box at random. What is the probability that number in the drawn slip is not a prime number? Correct Answer <span class="math-tex">\(47 \over62\)</span>

Given:

29, 30, 31, ........, 88, 89, 90.

Formula used:

P(E) = Sum of the favourable outcomes to E/ Total number of outcomes.

E represents the event.

Prime numbers are those numbers which are divisible by its number only.

Calculation:

Let E is the event of the outcomes which are non prime numbers which lies between from 29 to 90.

Prime numbers = 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89

Total outcomes = 62

Not a prime numbers(E) = 62 - 15

⇒ 47

P(E) = 47/62.

∴ 47/62 is the probability of drawing the slip which is not a prime number.

 

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