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What is the output of following program? abstract class Sum { public abstract int sumOfTwo(int n1, int n2); public abstract int sumOfThree(int n1, int n2, int n3); public void disp( ){ System.out.println("Method of class Sum"); } } class DemoAbstract1 extends Sum { public int sumOfTwo(int num1, int num2) { return num1+num2; } public int sumOfThree(int num1, int num2, int num3) { return num1+num2+num3; } public static void main(String args[ ]){ Sum obj = new DemoAbstract1( ); System.out.println(obj.sumOfTwo(3, 7)); System.out.println(obj.sumOfThree(4, 3, 19)); obj.disp( ); } }
A student wrote two context-free grammars G1 and G2 for generating a single C-like array declaration. The dimension of the array is at least one. For example, int a[10] [3] ; The grammars use D as the start symbol, and use six terminal symbols int; id[ ] num Grammar G1 Grammar G2 D → int L; D → int L; L → id[E L → idE E → num] E → E[num] E → num][E E → [num]   Which of the grammars correctly generate the declaration mentioned above?
Which of the following is good coding practice to determine oddity?
i)
public boolen abc(int num){return num % 2 == 1;}

ii)
public boolean xyz(int num){return (num & 1)!= 0; }
What is the right choice, if the following loop is implemented?
void main(){ int num = 0; do{ --num; printf("%d", num); }while( ++num >= 0 );}
Consider the function fun1 shown below:   int fun1 (int num) {   int count = 0;   while (num)   { count ++;   num ≫= 1;   }   return (count); } The value returned by fun1 (435) is
What will be the content of num, after code execution; if before code execution num has value 200?
If num500 Num=num*3;Endif
What will be the content of num, after the code execution; if before code execution num has value 90?
If num500 Num=num*3;Endif
What will be the content of num, after code execution; if before code execution num has value 1000?
If num500 Num=num*3;Endif
What will be the output of the following PHP code?
What is the output of this program ? #include
using namespace std;
int n(char, int);
int (*p) (char, int) = n;
int main()
{
(*p)('d', 9);
p(10, 9);
return 0;
}
int n(char c, int i)
{
cout << c << i;
return 0;
}