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Find maximum sliding velocity in cm/s from the given data addendum = 1 module = 5mm Pitch line speed = 1.2m/s Pressure angle of involute profile: 20 degrees Tp = 20 Gear ratio = 2

Find maximum sliding velocity in cm/s from the given data addendum = 1 module = 5mm Pitch line speed = 1.2m/s Pressure angle of involute profile: 20 degrees Tp = 20 Gear ratio = 2 Correct Answer 45.5

We know that V = ω1r = ω2R 120/(mt/2) = ω1 ω1 = 24 rad/s similarly ω2 = 12 rad/s Now maximum sliding velocity = (ω2 + ω1)x(length of path of approach) = 455.4 mm/s = 45.5 cm/s.

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