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Two involute gears have a pressure angle of 20°. The gear ratio is given to be 3. The module is 5 mm and the value of addendum is equal to 1 module. Determine the minimum number of teeth on each wheel to avoid interference, if the pinion rotates at 100 rpm.

Two involute gears have a pressure angle of 20°. The gear ratio is given to be 3. The module is 5 mm and the value of addendum is equal to 1 module. Determine the minimum number of teeth on each wheel to avoid interference, if the pinion rotates at 100 rpm. Correct Answer T = 45, t =15

Giveφ = 20°, G = T/t = 3, m = 5 mm and addendum = 1 module. Now, T = (2aw/(1+(1/G)((1/G)+2)sin2φ)0.5 – 1) is the minimum number of teeth on the larger gear. T = ((2×1)/(1+(1/3)((1/3)+2)sin2(20))0.5 – 1) = 44.94 ~ 45. Therefore, T = 45 and t = 45/3 = 15.

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