The angular velocity of the pinion is 325 rpm and that of the gear is 155 rpm. The number of teeth on the larger wheel is 60 and the module is equal to 7 mm. Addendum is 1.1 times the module. The pressure angle is 20°. Find the velocity of sliding at the beginning of the contact.
The angular velocity of the pinion is 325 rpm and that of the gear is 155 rpm. The number of teeth on the larger wheel is 60 and the module is equal to 7 mm. Addendum is 1.1 times the module. The pressure angle is 20°. Find the velocity of sliding at the beginning of the contact. Correct Answer 1010.858 mm/s
Np = 325 rpm. Therefore, ωp= 34.034 rad/s Ng = 155 rpm. Therefore, ωg= 16.231 rad/s m = 7 mm, T = 60 mm and R = mT/2 = 210 mm Ra = R + a = 210 + 7.7 = 217.7 mm Path of approach= (Ra2 – R2cos2 φ)0.5 – Rsinφ = 20.11 mm Velocity of sliding = (ωp + ωg) x Path of recess = (34.034 + 16.231) x 20.11 = 1010.858 mm/s.
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Feb 20, 2025