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The angular velocity of the pinion is 75 rpm and that of the gear is 25 rpm. The addendum radius is 45 mm for the pinion and the radius of the pinion is 40 mm. The pressure angle between the gears is 25°. Find the velocity of sliding at the end of the contact.

The angular velocity of the pinion is 75 rpm and that of the gear is 25 rpm. The addendum radius is 45 mm for the pinion and the radius of the pinion is 40 mm. The pressure angle between the gears is 25°. Find the velocity of sliding at the end of the contact. Correct Answer 97.77 mm/s

Np = 75 rpm. Therefore, ωp= 7.854 rad/s Ng = 25 rpm. Therefore, ωg= 2.168 rad/s r = 40 mm, ra = 45 mm, φ = 25° Path of recess = (ra2 – r2cos2 φ)0.5 – rsinφ = 9.755 mm Velocity of sliding = (ωp + ωg) x Path of recess = (7.854 + 2.168) x 9.755 = 97.77 mm/s.

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