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Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of normal force in Kg?

Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of normal force in Kg? Correct Answer 20.17

tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Normal force=-Cutting force*sin (shear angle)+feed force*cos(shear angle).

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