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Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of the shear angle in degrees?

Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of the shear angle in degrees? Correct Answer 20.17

tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Where r is the chip thickness ratio.

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