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A tensile rod of 40kN is acting on a rod of diameter 40mm and of length 4m. a bore of diameter 20mm is made centrally on the rod. To what length the rod should be bored so that the total extension will increase 30% under the same tensile load if E = 2×105 N/mm2?

A tensile rod of 40kN is acting on a rod of diameter 40mm and of length 4m. a bore of diameter 20mm is made centrally on the rod. To what length the rod should be bored so that the total extension will increase 30% under the same tensile load if E = 2×105 N/mm2? Correct Answer 3.6m

The extension = PL / AE = 2/π mm Extension after the bore is made = 1.3x 2/π mm = 2.6/π mm The extension after the bore is made, is also obtained by finding the extension of the un bored length and bored length. Stress = load / area So total extension after bore is made can have two equations which can be put equal and the length the rod should be bored up is calculated.

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