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In the Zener controlled series regulator shown below, find the current through the Zener diode. Given that the Zener diode breakdown voltage is 5V, the source voltage is 15V, the output voltage is 10V, R4 = 2kΩ, β=99, R1=2kΩ.

In the Zener controlled series regulator shown below, find the current through the Zener diode. Given that the Zener diode breakdown voltage is 5V, the source voltage is 15V, the output voltage is 10V, R4 = 2kΩ, β=99, R1=2kΩ. Correct Answer 4.95 mA

IE = IL = (100)IB IB = 10/100×2000 = 0.05 mA Current through R1 = IB + IZ = I1 IZ = I1 -IB = 15-5/2k – 0.05 = 5 – 0.05 = 4.95mA.

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