A transistor is connected in CE configuration. Collector supply voltage Vcc=10V, RL=800Ω, voltage drop across RL=0.8V, α=0.96. What is base current?

A transistor is connected in CE configuration. Collector supply voltage Vcc=10V, RL=800Ω, voltage drop across RL=0.8V, α=0.96. What is base current? Correct Answer 41.97µA

Here, IC=0.8/800=1mA β= α/ (1-α)=0.96/1-0.96=24. Now, IB=IC/ β=1/24=41.67µA.
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