For a flat open-belt drive, the belt speed is 880 m/min and the power transmitted is 22.5 kW. What is the difference between the tight side and slack side tensions of the belt drive?

Power is transmitted by an electric motor to a machine by using a belt drive. The tensions on the tight and slack side of the belt are 2200 N and 1000 N respectively and diameter of the pulley is 600 mm. If speed of the motor is 1500 r.p.m, find the power transmitted.

A

46.548 kW

B

56.548 kW

C

66.548 kW

D

76.548 kW

The ratio of driving tensions for flat belts, neglecting centrifugal tension, is (where T₁ and T₂ = Tensions on the tight and slack sides of belt respectively, $$\mu $$ = Coefficient of friction, between the belt and pulley and $$\theta $$ = Angle of contact)

A

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \mu \theta $$

B

$$\log \frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \mu \theta $$

C

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = {\text{e}}\mu \theta $$

D

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \log \mu \theta $$

In belt drive power transmitted is given by: (Where Tt, Ts, and v are tight side tension, slack side tension and linear velocity of belt respectively)

A

$\frac{{\left( {{T_t} - {T_s}} \right)}}{{2v}}$

B

$ \frac{{\left( {{T_t} + {T_s}} \right)}}{{2v}}$

C

(T_t - T_s)v

D

(T_t + T_s)v

Consider the following statements regarding V-belt drive : 1. The groove angle of the sleeve is less than the belt section angle 2. The efficiency of a V-belt drive is higher than that of a flat belt drive 3. The groove angle is so made that the belt gets wedged in the groove Which of the above statements are correct ?

A

1, 2 and 3

B

1 and 2 only

C

1 and 3 only

D

2 and 3 only

If T₁ and T₂ are the tensions on the tight and slack sides of the belt respectively and T_C is the centrifugal tension, then initial tension in the belt is equal to

A

T₁ - T₂ + T_C

B

T₁ + T₂ + T_C

C

$$\frac{{{{\text{T}}_1} - {{\text{T}}_2} + {{\text{T}}_{\text{C}}}}}{2}$$

D

$$\frac{{{{\text{T}}_1} + {{\text{T}}_2} + {{\text{T}}_{\text{C}}}}}{2}$$

If P₁ and P₂ are the tight and slack side tensions in the belt, then the initial tension P_i (according to Barth) will be equal to (Where, P_c is centrifugal tension)

A

$${\left( {\frac{{\sqrt {{{\text{P}}_1}} + \sqrt {{{\text{P}}_2}} }}{2}} \right)^2}$$

B

$${{\text{P}}_1} + {{\text{P}}_2}$$

C

$$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right)$$

D

$$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right) + {{\text{P}}_{\text{c}}}$$

If P₁ and P₂ are the tight and slack side tensions in the belt, then the initial tension P_i (neglecting centrifugal tension) will be equal to (Where, P_c is centrifugal tension)

A

$${{\text{P}}_1} - {{\text{P}}_2}$$

B

$${{\text{P}}_1} + {{\text{P}}_2}$$

C

$$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right)$$

D

$$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right) + {{\text{P}}_{\text{c}}}$$

The ratio of belt tensions $$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}$$ considering centrifugal force in flat belt is given by where,
m = mass of belt per meter (kg/m)
v = belt velocity (m/s)
f = coefficient of friction
$$\alpha $$ = angle of wrap (radians)

A

$$\frac{{{{\text{p}}_1} - {\text{m}}{{\text{v}}^2}}}{{{{\text{p}}_2} - {\text{m}}{{\text{v}}^2}}} = {{\text{e}}^{{\text{f}}\alpha }}$$

B

$$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}} = {{\text{e}}^{{\text{f}}\alpha }}$$

C

$$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}} = {{\text{e}}^{ - {\text{f}}\alpha }}$$

D

$$\frac{{{{\text{p}}_1} - {\text{m}}{{\text{v}}^2}}}{{{{\text{p}}_2} - {\text{m}}{{\text{v}}^2}}} = {{\text{e}}^{ - {\text{f}}\alpha }}$$

In a band and block brake, the ratio of tensions on tight side and slack side of the band is (where $$\mu $$ = Coefficient of friction between the blocks and the drum, $$\theta $$ = Semi-angle of each block subtending at the center of drum and n = Number of blocks)

A

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \mu \theta {\text{n}}$$

B

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = {\left( {\frac{{1 - \mu \tan \theta }}{{1 + \mu \tan \theta }}} \right)^{\text{n}}}$$

C

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = {\left( {\mu \theta } \right)^{\text{n}}}$$

D

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = {\left( {\frac{{1 + \mu \tan \theta }}{{1 - \mu \tan \theta }}} \right)^{\text{n}}}$$

The efficiency of flat belt drive is 35%. If all the parameters are same and flat belt is replaced by V belt, than the efficiency of V belt will be?

A

<35%

B

>35%

C

=35%

D

Cant be determined

For a flat open-belt drive, the belt speed is 880 m/min and the power transmitted is 22.5 kW. What is the difference between the tight side and slack side tensions of the belt drive?

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