The ratio of belt tensions $$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}$$ considering centrifugal force in flat belt is given by where,<br>m = mass of belt per meter (kg/m)<br>v = belt velocity (m/s)<br>f = coefficient of friction<br>$$\alpha $$ = angle of wrap (radians)

The ratio of driving tensions for flat belts, neglecting centrifugal tension, is (where T₁ and T₂ = Tensions on the tight and slack sides of belt respectively, $$\mu $$ = Coefficient of friction, between the belt and pulley and $$\theta $$ = Angle of contact)

A

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \mu \theta $$

B

$$\log \frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \mu \theta $$

C

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = {\text{e}}\mu \theta $$

D

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} = \log \mu \theta $$

A stream of air at 100 kPa pressure and 300 K is flowing on the top surface of a thin flat sheet of solid naphthalene of length 0.2 m with a velocity of 20 m/sec. The other data are: Mass diffusivity of naphthalene vapor in air = 6 * 10 –6 m2/sec Kinematic viscosity of air = 1.5 * 10 –5 m2.sc Concentration of naphthalene at the air-solid naphthalene interface = 1 * 10 – 5 kmol/m3 Calculate the overage mass transfer coefficient over the flat plate. Note: For heat transfer over a flat plate, convective heat transfer coefficient for laminar flow can be calculated by the equation. Nu = 0.664 ReL1/2 Pr1/3 you may use analogy between mass and heat transfer.

A

0.014 m/sec

B

0.015 m/sec

C

0.016 m/sec

D

0.013 m/sec

Consider the following statements regarding V-belt drive : 1. The groove angle of the sleeve is less than the belt section angle 2. The efficiency of a V-belt drive is higher than that of a flat belt drive 3. The groove angle is so made that the belt gets wedged in the groove Which of the above statements are correct ?

A

1, 2 and 3

B

1 and 2 only

C

1 and 3 only

D

2 and 3 only

Six flats A, B, C, D, E and F are located in two rows of three flats each. The flats in both the rows face each other. Flat D is diagonally opposite to flat C. Flat E is opposite to flat F, which is north facing. Flat C is 2nd to the left of A and both of flats are south facing. Which of the following flats is facing flat B?

A

C

B

A

C

D

F

A lady wants to buy the following items in the given price range- 1. Tomato between Rs. 40 and Rs. 45 per kg. 2. Grapes in the price range of Rs. 80 and Rs. 90 per kg. 3. Milk packets at Rs. 23 per liter. In which shop from the following will she definitely get all her items/ A. Shop S sells tomato at Rs. 22.5 per half kg, Grapes at Rs. 82 per kg and milk at Rs. 24 per liter. B. Shop H sells grapes at Rs. 21 per quarter kg, milk at 12.5 per half litre and tomato at Rs. 22 per half kg. C. Shop O sells milk at Rs. 11.5 per half litre, tomato at 21 per half kg and grapes at Rs. 43 per half kg. D. Shop P sells tomato at Rs. 23.5 per half kg, grapes at Rs. 85 per kg and milk at Rs. 23 per litre.

A

B

D

C

B

D

C

What is the monoisotopic and average mass of valine? Given data: Mass of the most abundant isotope of Carbon (C°)=12.0000, Mass of most abundant isotope of Hydrogen (H°)=1.0078, Mass of most abundant isotope of Oxygen (O°)=15.9949, Mass of most abundant isotope of Nitrogen (N°)=14.0031, The average mass of Carbon (C)=12.011, The average mass of Hydrogen (H)=1.008, The average mass of Oxygen (O)=15.999, The average mass of Nitrogen (N)=14.007.

A

99.068 and 99.2361

B

99.216 and 99.326

C

99.111 and 99.321

D

99.068 and 99.132

For a flat open-belt drive, the belt speed is 880 m/min and the power transmitted is 22.5 kW. What is the difference between the tight side and slack side tensions of the belt drive?

A

900 N

B

6450 N

C

1535 N

D

1000 N

The efficiency of flat belt drive is 35%. If all the parameters are same and flat belt is replaced by V belt, than the efficiency of V belt will be?

A

<35%

B

>35%

C

=35%

D

Cant be determined

When the belt is transmitting maximum power, the belt speed should be (Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N))

A

$$\sqrt {\frac{{{\text{P}}\max }}{{2{\text{m}}}}} $$

B

$$\sqrt {\frac{{{\text{P}}\max }}{{3{\text{m}}}}} $$

C

$$\sqrt {\frac{{{\text{P}}\max }}{{\text{m}}}} $$

D

$$\sqrt {\frac{{{\text{3m}}}}{{{\text{P}}\max }}} $$

When the belt is transmitting maximum power, the belt speed should be
(Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N))

A

$$\sqrt {\frac{{{\text{P}}\max }}{{2{\text{m}}}}} $$

B

$$\sqrt {\frac{{{\text{P}}\max }}{{3{\text{m}}}}} $$

C

$$\sqrt {\frac{{{\text{P}}\max }}{{\text{m}}}} $$

D

$$\sqrt {\frac{{{\text{3m}}}}{{{\text{P}}\max }}} $$

The ratio of belt tensions $$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}$$ considering centrifugal force in flat belt is given by where,
m = mass of belt per meter (kg/m)
v = belt velocity (m/s)
f = coefficient of friction
$$\alpha $$ = angle of wrap (radians)

Related Questions

The ratio of belt tensions $$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}$$ considering centrifugal force in flat belt is given by where,m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of friction$$\alpha $$ = angle of wrap (radians)

Related Questions

The ratio of belt tensions $$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}$$ considering centrifugal force in flat belt is given by where,
m = mass of belt per meter (kg/m)
v = belt velocity (m/s)
f = coefficient of friction
$$\alpha $$ = angle of wrap (radians)