In an election held in a town, the voting percentage was 83.33%. The winner got 33.33% of the polled votes, while the runner-up got 22.22% of the polled votes. If there were 108054 voters in the town, by how many votes did the winner win the election?

In an election held in a town, the voting percentage was 83.33%. The winner got 33.33% of the polled votes, while the runner-up got 22.22% of the polled votes. If there were 108054 voters in the town, by how many votes did the winner win the election? Correct Answer 10005

Given:

In an election held in a town, the voting percentage was 83.33%.

The winner got 33.33% of the polled votes, while the runner-up got 22.22% of the polled votes.

There were 108054 voters in the town.

Formula used:

Percentage = (value/total value) × 100

Calculation:

Total no. of voters = 108054

Voting percentage = 83.33%

No. of votes = 83.33% of 108054

⇒ 5/6 × 108054

⇒ 90045

Now,

Percentage of votes received by winner = 33.33%

Percentage of votes received by runner-up = 22.22%

Percentage of votes by which the winner won = 33.33 – 22.22

⇒ 11.11%

No. of votes by which the winner won the election = 11.11% of 90045

⇒ 1/9 × 90045

⇒ 10005

∴ 10005 votes the winner win in the election.

Related Questions

Each question below is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer. In an election there are three candidates A, B and C.What is the difference between the votes received by A and C if 15% of voters in the city didn't cast their vote? I A got 40% votes and got 7650 less votes than combined votes of B and C. Difference between the votes of B and C is 1850. B got more votes than C. II To win the election a candidate requires 33% of the total eligible votes and A won the election by 450 votes.