Bissoy.com
Doctors Medicines MCQs Q&A

Radha reaches company 10 min late when she travels at a speed of 20kmph and she reaches 20 min early if she travels at a speed of 30kmph. At what speed she should travel to cover the office distance in 2 hours?

Radha reaches company 10 min late when she travels at a speed of 20kmph and she reaches 20 min early if she travels at a speed of 30kmph. At what speed she should travel to cover the office distance in 2 hours? Correct Answer 15 kmph

GIVEN :

Radha reaches company 10 min late when she travels at a speed of 20kmph

She reaches 20 min early if she travels at a speed of 30kmph.

 

CONCEPT :

Speed , Time & Distance

 

ASSUMPTION :

Let the office distance for Radha be M km.

 

CALCULATION :

Difference in time = 10 + 20 = 30 min = 30/60 hours

Relative speed = M/20 - M/30

⇒ M/20 - M/30 = 1/2

⇒ 10M/600 = 1/2

⇒ M = 30

The office distance for Radha is 30km.

∴ Required speed = distance/speed = 30/2 = 15kmph

 

Related Questions

If Rati travels at his usual speed for ‘x’ hours, he covers the same distance as he covered when he travels at a speed 30 km/hr less than usual, but for (x + 3) hours. Which of the following can be determined? (A) If he travels at 20 km/hr less speed than usual, he can cover a distance of 240 km in (x - 1) hours. What is the value of ‘x’? (B) If travels at his usual speed for (t + 2) hours, and at 50% of his usual speed for (t - 2) hours, his average speed for the journey is 68 km/hr. What is his usual speed? (C) His usual speed (in km/hr) is a multiple of 5 between 40 and 50 (both inclusive). If ‘x’ is a whole number, what is his usual speed? (D) If he travels at his usual speed for ‘t’ hours, he covers a distance of 400 km. What is the value of ‘x’?
A person travels a certain distance at 3 km/hr and reaches 15 mi late. If he travels at 4 km/hr reaches 15 min late. If he travels at 4 km/hr reaches 15 min earlier. The distance he has to travel is -
The distance between S and T is 200 km. Radha travels from point S at a speed of 20 km/h and reaches point U in 2 hours, after that she travels at a speed of 25 percent more than previous and reaches point V in 4 hours, then find how many percent she decreases in her speed to travel the remaining distance in 6 hours.
Rehana leaves her home early in the morning so that she can reach her office on time. If she walks at the rate of 7 km/hr, then she reaches her office 8 minutes late. But, if she walks at a speed of 8 km/hr, then she reaches her office 4 minutes early. What is the distance in km between Rehana's house and her office?
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity A: A woman travels 2/5 of a journey by car, 9/20 by train and the remaining 12 km by cycle. The total distance of his journey is – Quantity B: when Radha goes to school by walk at the rate of 6 km/hr, she misses the school bell by 5 min. If she travels via bicycle at the rate of 7 km/hr then she reaches school 4 min before school bell. What is the distance between Radha’s school and her home?
Rehana leaves her home early in the morning so that she can reach her office on time. If she walks at the rate of 7 km/hr then she reaches her office 8 minutes late. But, if she walks at a speed of 8 km/hr, then she reaches her 4 minutes early. What is the distance in km between Rehana's house and her office?
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity A: A person who travels a certain distance to his office by his car.If he increases his speed by 8 km/hr, he takes 2 hours less time but if he drives 8 km/hr slower, he takes 4 hours more time. Find the distance of office from home. Quantity B: A person who travels a certain distance to his office by his car. If he increases his speed by 10 km/hr, he takes 1 hour less time but if he further increases his speed by 5 km/hr, he takes further 20 minutes lesser time. Find the distance of office from home.
A man reaches his office 30 min late, if he travel from his home at 30 km per hour and reaches 40 min early if he travel 40 km per hour. How far is his office from his home?
If a man goes to the office from his home with a speed 12 km/hr, he reaches the office 1 hour late. When he goes to the office with a speed of 16 km/hr, he reaches the office 1 hour early then find the distance between the home and the office (in kilo meters).
Each of the question below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. If the bus is travelling from Surat to Ahmadabad and a car is travelling from Ahmadabad to Surat, then what is the distance between Surat and Ahmadabad? I. The speed of a car is 40% less than the speed of bus. Bus started at 9 am and car started at 10 am and they meet at 3 pm of the same day. II. After travelling for 1 hour, because of traffic average speed of bus is decreased by 20% and covers distance between Surat to Ahmadabad in 11 hours. Original speed of car is 20% less than original speed of bus and before crossing bus it covered 200 km if starts 1 hour later than bus. After crossing car, bus covers remaining distance in 5 hours. III. Speed of bus is 10 km/hr more than the speed of car and before crossing car ratio of distances covered bus and car in same time was 5 : 4. Time taken by car to cover the distance between Ahmadabad and Surat is 2 hours 15 minutes more than time taken by bus to cover the same distance.