A person travels a certain distance at 3 km/hr and reaches 15 mi late. If he travels at 4 km/hr reaches 15 min late. If he travels at 4 km/hr reaches 15 min earlier. The distance he has to travel is -

A 8.5 km
B 6 km
C 7.2 km
D 12 km

Correct Answer: 6 km

Let,Distance  =  x km ATQ, x3 - x4 = 12hours⇒4x - 3x12 = 12.'. x = 6 
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