The Table presents the amount of milk (in litres) sold by two milkmen in eight days. Days Milkman 1 Milkman 2 1 28 31 2 34 32 3 38 43 4 37 41 5 53 49 6 58 59 7 63 62 8 67 69   The total amount of milk (in litres) sold by milkman 2 in all 8 days is what percent (correct to one decimal place) more than the total amount of milk sold by milkman 1 in first six days?

The Table presents the amount of milk (in litres) sold by two milkmen in eight days. Days Milkman 1 Milkman 2 1 28 31 2 34 32 3 38 43 4 37 41 5 53 49 6 58 59 7 63 62 8 67 69   The total amount of milk (in litres) sold by milkman 2 in all 8 days is what percent (correct to one decimal place) more than the total amount of milk sold by milkman 1 in first six days? Correct Answer 55.6

The total amount of milk (in litres) sold by milkman 2 in all 8 days = 31 + 32 + 43 + 41 + 49 + 59 + 62 + 69 = 386

⇒ The total amount of milk sold by milkman 1 in first six days = 28 + 34 + 38 + 37 + 53 + 58 = 248

⇒ Required % = × 100 = (138/248) × 100 = 55.6%

∴ Require percentage is 55.6

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