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Nine years later, the age of B will be equal to the present age of A. Sum of A's age 3 years later and B's age 4 years ago will be 76. If the age of C is half of the present age of B, then what will be C's age (in years) after 10 years?

Nine years later, the age of B will be equal to the present age of A. Sum of A's age 3 years later and B's age 4 years ago will be 76. If the age of C is half of the present age of B, then what will be C's age (in years) after 10 years? Correct Answer 27

Let the present age of A be ‘x’

Thus, nine years later B’ s age = x

Therefore, present age of B = (x - 9)

According to question,

Sum of A's age 3 years later and B's age 4 years ago is 76

⇒ (x + 3) + {(x - 9) - 4} = 76

⇒ × = 43

Thus, A’ s present age = 43

B’ s present age = 43 - 9 = 34

Given,

The age of C is half of the present age of B ⇒ C’ s present age = 17

Therefore, C’ s age after 10 years = 17 + 10 = 27.

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