Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly. Quantity I: 3 years ago the ratio of age of A and B is 3: 4 after 2 years the sum of their ages is 45. Then find the present age of A? Quantity II: 5 years ago, the ratio of age of p and Q id 3: 4 Ps age after 6 years is equal to the present age of Q. the find the present age of P?

Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly. Quantity I: 3 years ago the ratio of age of A and B is 3: 4 after 2 years the sum of their ages is 45. Then find the present age of A? Quantity II: 5 years ago, the ratio of age of p and Q id 3: 4 Ps age after 6 years is equal to the present age of Q. the find the present age of P? Correct Answer Quantity I < Quantity II

Quantity I= Let 3 year ago the age of A and B be 3x and 4x respectively

Then ATQ 3x+5+4x+5=45 X=5

Hence present age of A=3x+3=18year

Quantity II== Let 5 year ago the age of p and q be 3x and 4x respectively 

Then ATQ 

3x+11=4x+5 

X=6 Hence present age of P=3x+5=23

Hence Quantity I < Quantity II

 

 

Related Questions

Each question below is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of mathematics to choose the best possible answer. The present age of A is 2/5 of the present age of B then what are their ages. Statement I: After 10 years, the ratio of their ages will become 4 : 7 Statement II: 4 years ago, the ratio of their ages was 2 : 7